In basic solution, Se2− and SO3

2− ions react spontaneously:

2Se2−(aq) + 2SO3

2−(aq) + 3H2O(l) ⟶

2Se(s) + 6OH−(aq) + S2O3

2−(aq) E°

cell = 0.35 V

(a) Write balanced half-reactions for the process.

(b) If E°sulfite is −0.57 V, calculate E°selenium.