Na2CO3(aq) + CaCl2(aq) ——– 2NaCl(aq) + CaCO3 (s)

Calculate the volume (in mL) of 0.100 M CaCl2 needed to produce 1.00g of CaCO (s). There is an excess of Na2CO3

Molar mass of calcium carbonate= 100.09 g/mol

volume of calcium chloride =