Copper(I) oxide can be oxidized to copper(II) oxide: Cu2O(s) + 1⁄2 O2(g) →2CuO(s) ∆H°rxn = – 146.0 kJ
Given that ∆H°f of Cu2O(s) = -168.6 kJ/mol, what is ∆H°f of CuO(s)?
Copper(I) oxide can be oxidized to copper(II) oxide: Cu2O(s) + 1⁄2 O2(g) →2CuO(s) ∆H°rxn = – 146.0 kJ
Given that ∆H°f of Cu2O(s) = -168.6 kJ/mol, what is ∆H°f of CuO(s)?
